Optimal. Leaf size=156 \[ \frac {a x}{e}+\frac {b x \tanh ^{-1}(c x)}{e}+\frac {d \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{e^2}-\frac {d \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{e^2}+\frac {b \log \left (1-c^2 x^2\right )}{2 c e}-\frac {b d \text {PolyLog}\left (2,1-\frac {2}{1+c x}\right )}{2 e^2}+\frac {b d \text {PolyLog}\left (2,1-\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{2 e^2} \]
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Rubi [A]
time = 0.11, antiderivative size = 156, normalized size of antiderivative = 1.00, number of steps
used = 9, number of rules used = 7, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.412, Rules used = {6087, 6021,
266, 6057, 2449, 2352, 2497} \begin {gather*} \frac {d \log \left (\frac {2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{e^2}-\frac {d \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2 c (d+e x)}{(c x+1) (c d+e)}\right )}{e^2}+\frac {a x}{e}+\frac {b \log \left (1-c^2 x^2\right )}{2 c e}-\frac {b d \text {Li}_2\left (1-\frac {2}{c x+1}\right )}{2 e^2}+\frac {b d \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+e) (c x+1)}\right )}{2 e^2}+\frac {b x \tanh ^{-1}(c x)}{e} \end {gather*}
Antiderivative was successfully verified.
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Rule 266
Rule 2352
Rule 2449
Rule 2497
Rule 6021
Rule 6057
Rule 6087
Rubi steps
\begin {align*} \int \frac {x \left (a+b \tanh ^{-1}(c x)\right )}{d+e x} \, dx &=\int \left (\frac {a+b \tanh ^{-1}(c x)}{e}-\frac {d \left (a+b \tanh ^{-1}(c x)\right )}{e (d+e x)}\right ) \, dx\\ &=\frac {\int \left (a+b \tanh ^{-1}(c x)\right ) \, dx}{e}-\frac {d \int \frac {a+b \tanh ^{-1}(c x)}{d+e x} \, dx}{e}\\ &=\frac {a x}{e}+\frac {d \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{e^2}-\frac {d \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{e^2}-\frac {(b c d) \int \frac {\log \left (\frac {2}{1+c x}\right )}{1-c^2 x^2} \, dx}{e^2}+\frac {(b c d) \int \frac {\log \left (\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{1-c^2 x^2} \, dx}{e^2}+\frac {b \int \tanh ^{-1}(c x) \, dx}{e}\\ &=\frac {a x}{e}+\frac {b x \tanh ^{-1}(c x)}{e}+\frac {d \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{e^2}-\frac {d \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{e^2}+\frac {b d \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{2 e^2}-\frac {(b d) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+c x}\right )}{e^2}-\frac {(b c) \int \frac {x}{1-c^2 x^2} \, dx}{e}\\ &=\frac {a x}{e}+\frac {b x \tanh ^{-1}(c x)}{e}+\frac {d \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2}{1+c x}\right )}{e^2}-\frac {d \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{e^2}+\frac {b \log \left (1-c^2 x^2\right )}{2 c e}-\frac {b d \text {Li}_2\left (1-\frac {2}{1+c x}\right )}{2 e^2}+\frac {b d \text {Li}_2\left (1-\frac {2 c (d+e x)}{(c d+e) (1+c x)}\right )}{2 e^2}\\ \end {align*}
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Mathematica [C] Result contains complex when optimal does not.
time = 1.66, size = 315, normalized size = 2.02 \begin {gather*} \frac {2 a e x-2 a d \log (d+e x)+\frac {b \left (-i c d \pi \tanh ^{-1}(c x)+2 c e x \tanh ^{-1}(c x)-2 c d \tanh ^{-1}\left (\frac {c d}{e}\right ) \tanh ^{-1}(c x)+c d \tanh ^{-1}(c x)^2-e \tanh ^{-1}(c x)^2+\sqrt {1-\frac {c^2 d^2}{e^2}} e e^{-\tanh ^{-1}\left (\frac {c d}{e}\right )} \tanh ^{-1}(c x)^2+2 c d \tanh ^{-1}(c x) \log \left (1+e^{-2 \tanh ^{-1}(c x)}\right )+i c d \pi \log \left (1+e^{2 \tanh ^{-1}(c x)}\right )-2 c d \tanh ^{-1}\left (\frac {c d}{e}\right ) \log \left (1-e^{-2 \left (\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)\right )}\right )-2 c d \tanh ^{-1}(c x) \log \left (1-e^{-2 \left (\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)\right )}\right )+e \log \left (1-c^2 x^2\right )+\frac {1}{2} i c d \pi \log \left (1-c^2 x^2\right )+2 c d \tanh ^{-1}\left (\frac {c d}{e}\right ) \log \left (i \sinh \left (\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)\right )\right )-c d \text {PolyLog}\left (2,-e^{-2 \tanh ^{-1}(c x)}\right )+c d \text {PolyLog}\left (2,e^{-2 \left (\tanh ^{-1}\left (\frac {c d}{e}\right )+\tanh ^{-1}(c x)\right )}\right )\right )}{c}}{2 e^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 3.77, size = 243, normalized size = 1.56
method | result | size |
derivativedivides | \(\frac {\frac {a \,c^{2} x}{e}-\frac {a \,c^{2} d \ln \left (c e x +d c \right )}{e^{2}}+\frac {b \,c^{2} \arctanh \left (c x \right ) x}{e}-\frac {b \,c^{2} \arctanh \left (c x \right ) d \ln \left (c e x +d c \right )}{e^{2}}+\frac {b c \ln \left (c^{2} d^{2}-2 c d \left (c e x +d c \right )-e^{2}+\left (c e x +d c \right )^{2}\right )}{2 e}+\frac {b \,c^{2} d \ln \left (c e x +d c \right ) \ln \left (\frac {c e x +e}{-d c +e}\right )}{2 e^{2}}+\frac {b \,c^{2} d \dilog \left (\frac {c e x +e}{-d c +e}\right )}{2 e^{2}}-\frac {b \,c^{2} d \ln \left (c e x +d c \right ) \ln \left (\frac {c e x -e}{-d c -e}\right )}{2 e^{2}}-\frac {b \,c^{2} d \dilog \left (\frac {c e x -e}{-d c -e}\right )}{2 e^{2}}}{c^{2}}\) | \(243\) |
default | \(\frac {\frac {a \,c^{2} x}{e}-\frac {a \,c^{2} d \ln \left (c e x +d c \right )}{e^{2}}+\frac {b \,c^{2} \arctanh \left (c x \right ) x}{e}-\frac {b \,c^{2} \arctanh \left (c x \right ) d \ln \left (c e x +d c \right )}{e^{2}}+\frac {b c \ln \left (c^{2} d^{2}-2 c d \left (c e x +d c \right )-e^{2}+\left (c e x +d c \right )^{2}\right )}{2 e}+\frac {b \,c^{2} d \ln \left (c e x +d c \right ) \ln \left (\frac {c e x +e}{-d c +e}\right )}{2 e^{2}}+\frac {b \,c^{2} d \dilog \left (\frac {c e x +e}{-d c +e}\right )}{2 e^{2}}-\frac {b \,c^{2} d \ln \left (c e x +d c \right ) \ln \left (\frac {c e x -e}{-d c -e}\right )}{2 e^{2}}-\frac {b \,c^{2} d \dilog \left (\frac {c e x -e}{-d c -e}\right )}{2 e^{2}}}{c^{2}}\) | \(243\) |
risch | \(-\frac {b \ln \left (-c x +1\right ) x}{2 e}+\frac {b \ln \left (-c x +1\right )}{2 c e}-\frac {b}{c e}+\frac {b d \dilog \left (\frac {\left (-c x +1\right ) e -d c -e}{-d c -e}\right )}{2 e^{2}}+\frac {b d \ln \left (-c x +1\right ) \ln \left (\frac {\left (-c x +1\right ) e -d c -e}{-d c -e}\right )}{2 e^{2}}+\frac {a x}{e}-\frac {a}{c e}-\frac {a d \ln \left (\left (-c x +1\right ) e -d c -e \right )}{e^{2}}+\frac {b \ln \left (c x +1\right ) x}{2 e}+\frac {b \ln \left (c x +1\right )}{2 c e}-\frac {b d \dilog \left (\frac {\left (c x +1\right ) e +d c -e}{d c -e}\right )}{2 e^{2}}-\frac {b d \ln \left (c x +1\right ) \ln \left (\frac {\left (c x +1\right ) e +d c -e}{d c -e}\right )}{2 e^{2}}\) | \(255\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x \left (a + b \operatorname {atanh}{\left (c x \right )}\right )}{d + e x}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x\,\left (a+b\,\mathrm {atanh}\left (c\,x\right )\right )}{d+e\,x} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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